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# If sin(x) = 8/17 and x is an acute angle, find cot(x). Please draw a reference triangle

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If sin(x) = 8/17 and x is an acute angle, find cot(x). Please draw a reference triangle

Thank you!

Feb 25, 2021

#1
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Acute angle   so   sin and cos are positive    and so is cot = cos/sin

sin^2 + cos^2 = 1

cos ^2 = 1- (8/17)2 =  225 / 289

cos = 15/17

cot =   cos / sin = .........

Feb 25, 2021
#2
+593
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The question asked for a reference triangle.

Remember that sin is opposite over hypotenuse, meaning that the side opposite to angle with measure $x$ is $8$ and the hypotenuse is $17$. Use the Pythagorean theorem to find the other side. Then, use that $\cot(x)=\frac{\cos(x)}{\sin(x)}$, recalling that $\cos=\frac{\text{adjacent}}{\text{hypotenuse}}$.

(Remember: Soh Cah Toa!)

Feb 25, 2021