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If square root 3 minus 1 is a root of the equation 2x^2 - 2kx + 4=0 then k equals

Guest Nov 15, 2017

Best Answer 

 #1
avatar+623 
+2

ax+ bx + c = 0

 

To solve this problem, we need to use the formula X1*X2 = c ÷ a

 

(√3-1) * X= 4 ÷ 2

 X= 2/ √3-1

 

Using that, we can figure out k, 

 

Using this 

 

X+ X= -a/b

 

(2/√3-1) + (√3-1) = -(-2k/2)

 

We got k = 2√3

 

Can someone check over my work? Not sure about the answer, pretty sure the solution is right...

supermanaccz  Nov 15, 2017
 #1
avatar+623 
+2
Best Answer

ax+ bx + c = 0

 

To solve this problem, we need to use the formula X1*X2 = c ÷ a

 

(√3-1) * X= 4 ÷ 2

 X= 2/ √3-1

 

Using that, we can figure out k, 

 

Using this 

 

X+ X= -a/b

 

(2/√3-1) + (√3-1) = -(-2k/2)

 

We got k = 2√3

 

Can someone check over my work? Not sure about the answer, pretty sure the solution is right...

supermanaccz  Nov 15, 2017

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