solve using tn = a + (n-1)d... where a is the first term, d is the difference between terms and n is the number of the term, so in this case 10. How do I find a and d, or how do I find the tenth term?
Thanks
+130466
So we have
an = a1 +d(n - 1) the 4th term is 18 and the 16th term id 48 ......so we have.....
18 = a1 + d(4 - 1) → 18 = a1 + 3d
54 = a1 + d(16 -1) → 54 = a1 + 15d subtracting the first equation from the second, we have....
36 = 12d so ... d = 3
And using the first equation
18 = a1 + 3(3)
18 = a1 + 9 subtract 9 from each side
9 = a1
So....the 10th term is given by
a10 = 9 + 3(10 - 1)
a10 = 9 + 27 =
36
+130466
So we have
an = a1 +d(n - 1) the 4th term is 18 and the 16th term id 48 ......so we have.....
18 = a1 + d(4 - 1) → 18 = a1 + 3d
54 = a1 + d(16 -1) → 54 = a1 + 15d subtracting the first equation from the second, we have....
36 = 12d so ... d = 3
And using the first equation
18 = a1 + 3(3)
18 = a1 + 9 subtract 9 from each side
9 = a1
So....the 10th term is given by
a10 = 9 + 3(10 - 1)
a10 = 9 + 27 =
36
