If the adjacent is 60" and the opposite is 5" how long is the hypotenuse

Question

0

640

1

Guest May 7, 2014

+33658

+5

Best Answer

Use the Pythagoras theorem:

$hypotenuse=\sqrt{adjacent^2+opposite^2}$

Alan May 7, 2014

Alan · Answer 1 · 2014-05-07T11:22:03

Use the Pythagoras theorem:

$hypotenuse=\sqrt{adjacent^2+opposite^2}$