if the area of this rectangle is 84 then what if there is a x+2 on the length and a x+7 on the width
We have ..... Length * Width = Area .....so.....
(x +2) (x + 7) = 84 simplify
x^2 + 9x + 14 = 84 subtract 84 from each side
x^2 + 9x - 70 = 0 factor
(x - 5) (x + 14) = 0
And serring each factor to 0, we have that x = 5 or x = -14
Reject the second solution....so.....the length = (5 + 2) = 7 and the width = (5 + 7) = 12
We have ..... Length * Width = Area .....so.....
(x +2) (x + 7) = 84 simplify
x^2 + 9x + 14 = 84 subtract 84 from each side
x^2 + 9x - 70 = 0 factor
(x - 5) (x + 14) = 0
And serring each factor to 0, we have that x = 5 or x = -14
Reject the second solution....so.....the length = (5 + 2) = 7 and the width = (5 + 7) = 12