if the base of the triangle is 14 cm and its height is 10 cm. The hole is 5 cm across at its widest part. what would be the answer to three decimal places. (π = 3.14)
If you are trying to find the area that remains after cutting out a circular hole of 5cm diameter from the triangle then it is:
$${\mathtt{RemainingArea}} = \left({\frac{{\mathtt{1}}}{{\mathtt{2}}}}\right){\mathtt{\,\times\,}}{\mathtt{14}}{\mathtt{\,\times\,}}{\mathtt{10}}{\mathtt{\,-\,}}{\frac{{\mathtt{3.14}}{\mathtt{\,\times\,}}{{\mathtt{5}}}^{{\mathtt{2}}}}{{\mathtt{4}}}} \Rightarrow {\mathtt{RemainingArea}} = {\mathtt{50.375}}$$ cm2
Dude, what is your question? The answer to what? right angled triangle? angles? if any??
If you are trying to find the area that remains after cutting out a circular hole of 5cm diameter from the triangle then it is:
$${\mathtt{RemainingArea}} = \left({\frac{{\mathtt{1}}}{{\mathtt{2}}}}\right){\mathtt{\,\times\,}}{\mathtt{14}}{\mathtt{\,\times\,}}{\mathtt{10}}{\mathtt{\,-\,}}{\frac{{\mathtt{3.14}}{\mathtt{\,\times\,}}{{\mathtt{5}}}^{{\mathtt{2}}}}{{\mathtt{4}}}} \Rightarrow {\mathtt{RemainingArea}} = {\mathtt{50.375}}$$ cm2