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If the density of copper is 8.92 x 10^3 g/L and the density of magnesium is 1.74 x 10^3 g/L, what mass of magnesium occupies the same volume as 100.0 g of copper?

physics
Guest Oct 15, 2014

Best Answer 

 #1
avatar+26397 
+5

Density is mass per unit volume, so for the copper we have

 

8.92*10^3= 100/V  so V = 100/(8.92*10^3)  = 1/89.2 L

 

For magnesium:   1.74*10^3 = M/(1/89.2)  so  M = 1.74*10^3/89.2 ≈ 19.51 g

 

.

Alan  Oct 15, 2014
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1+0 Answers

 #1
avatar+26397 
+5
Best Answer

Density is mass per unit volume, so for the copper we have

 

8.92*10^3= 100/V  so V = 100/(8.92*10^3)  = 1/89.2 L

 

For magnesium:   1.74*10^3 = M/(1/89.2)  so  M = 1.74*10^3/89.2 ≈ 19.51 g

 

.

Alan  Oct 15, 2014

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