If the first three terms of an arithmetic progression are (x+3). (3x-10) and (2x+12), find x.

(3x-10) - (x+3) = (2x+12) - (3x-10), solve for x

x=35/3 and the common difference =31/3. So:

First term =44 / 3

2nd term = 25

3rd term =106/3