If the function y = (sqrt(-2(x+a)) +a passes through the point (-8,8) then the values of a is?
Just substitute in the values for x and y then you have an equation for a:
8 - a = sqrt(-2(-8+a))
a^2 -16a+64=-2(a-8)
a^2 -14a+48=0
(a-6)(a-8)=0 Therefore a = 6 or a = 8
Just substitute in the values for x and y then you have an equation for a:
8 - a = sqrt(-2(-8+a))
a^2 -16a+64=-2(a-8)
a^2 -14a+48=0
(a-6)(a-8)=0 Therefore a = 6 or a = 8