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If the hypotenuse of a triangle is x and the shortest leg is x/4 then what's the length of the remaining side?

 Mar 13, 2015

Best Answer 

 #1
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We have, by the Pythagorean Theorem....

√ [x^2 - (x/4)^2] =

√ [(16x^2 - x^2) / 16]=

[√(15)/4 ] x

 

  

 Mar 13, 2015
 #1
avatar+130516 
+5
Best Answer

We have, by the Pythagorean Theorem....

√ [x^2 - (x/4)^2] =

√ [(16x^2 - x^2) / 16]=

[√(15)/4 ] x

 

  

CPhill Mar 13, 2015
 #2
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0

i answer the question with a question. what mindset do you have to be in to understand this? its like hyrogleiphics. 

 Mar 13, 2015

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