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If the lengths of the bases of an isosceles trapezoid inscribed in a circle are 10 cm and 22 cm, and if one of the legs is 10 cm, then the length of a diagonal, in cm, is?

 

a) 6√10

b) 8√5

c) 6√3

d) 10√3

e) 12√2

 Jan 2, 2018
 #1
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We can find the height of this trapezoid as follows.....

 

h =  sqrt [ 10^2   -  6^2]  =  sqrt [100 - 36 ]  =  sqrt [ 64]  =   8

 

And the length  of the diagonal  will be the hypotenuse of a right triangle with legs of 8  and 16

 

So....the diagonal   is

 

sqrt  [ 8^2  +  16^2]  =    sqrt  [  8^2  ( 1  + 2^2) ]  =   8 sqrt (5)  units

 

 

cool cool cool

 Jan 2, 2018

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