If the perimeter of a rhombus is 40 and one of its diagonals is 12, Find the other diagonal.
Since the sides of a rhombus are equal, then one side must be = 10
And the diagonals bisect each other and are at right angles to each other...thus, we can use the Pythagorean Theorem to find the length (D) of the other diagonal.....the side length is the hypoteneuse and (1/2) the length of the known diagonal is a leg...so we have....
(1/2)D = √(10^2 - 6^2) = √(100-36) = √64 = 8
And we just need to double this to find the length of the other diagonal = 16
Since the sides of a rhombus are equal, then one side must be = 10
And the diagonals bisect each other and are at right angles to each other...thus, we can use the Pythagorean Theorem to find the length (D) of the other diagonal.....the side length is the hypoteneuse and (1/2) the length of the known diagonal is a leg...so we have....
(1/2)D = √(10^2 - 6^2) = √(100-36) = √64 = 8
And we just need to double this to find the length of the other diagonal = 16