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If the product of six different integers is 120000, what is the greatest possible value for one of the integers?

Answer: 1000

 Jan 27, 2017
 #1
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Answer=1000

 Jan 27, 2017
 #2
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I'm assuming all positive integers....to see why this is true.....note.....

 

5!  = 1 * 2 * 3 * 4 * 5  = 120 ........this minimizes the product of the 1st five integers

 

So...... 5! * 1000  = 120000  [ any integer > 1000 will produce a product > 120000 ]

 

 

cool cool cool

 Jan 27, 2017

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