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if the side of this isosceles triangle are 12cm and base is 8cm whats the height

 Jul 9, 2015

Best Answer 

 #1
avatar+14537 
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a = b = 12 cm      ;  c = 8 cm


Pythagoras:       h² + (c/2)² = a²


                         h² = 144 - 16        =>     h =$${\sqrt{{\mathtt{144}}{\mathtt{\,-\,}}{\mathtt{16}}}}$$


$${\mathtt{h}} = {\sqrt{{\mathtt{144}}{\mathtt{\,-\,}}{\mathtt{16}}}} \Rightarrow {\mathtt{h}} = {\mathtt{11.313\: \!708\: \!498\: \!984\: \!760\: \!4}}$$    cm

 Jul 9, 2015
 #1
avatar+14537 
+5
Best Answer

a = b = 12 cm      ;  c = 8 cm


Pythagoras:       h² + (c/2)² = a²


                         h² = 144 - 16        =>     h =$${\sqrt{{\mathtt{144}}{\mathtt{\,-\,}}{\mathtt{16}}}}$$


$${\mathtt{h}} = {\sqrt{{\mathtt{144}}{\mathtt{\,-\,}}{\mathtt{16}}}} \Rightarrow {\mathtt{h}} = {\mathtt{11.313\: \!708\: \!498\: \!984\: \!760\: \!4}}$$    cm

radix Jul 9, 2015

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