if the side of this isosceles triangle are 12cm and base is 8cm whats the height

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if the side of this isosceles triangle are 12cm and base is 8cm whats the height

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if the side of this isosceles triangle are 12cm and base is 8cm whats the height

Guest Jul 9, 2015

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a = b = 12 cm ; c = 8 cm

Pythagoras: h² + (c/2)² = a²

h² = 144 - 16 => h = ${\sqrt{{\mathtt{144}}{\mathtt{\,-\,}}{\mathtt{16}}}}$

${\mathtt{h}} = {\sqrt{{\mathtt{144}}{\mathtt{\,-\,}}{\mathtt{16}}}} \Rightarrow {\mathtt{h}} = {\mathtt{11.313\: \!708\: \!498\: \!984\: \!760\: \!4}}$ cm

radix Jul 9, 2015

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radix · Answer 1 · 2015-07-09T12:30:58

a = b = 12 cm ; c = 8 cm

Pythagoras: h² + (c/2)² = a²

h² = 144 - 16 => h = ${\sqrt{{\mathtt{144}}{\mathtt{\,-\,}}{\mathtt{16}}}}$

${\mathtt{h}} = {\sqrt{{\mathtt{144}}{\mathtt{\,-\,}}{\mathtt{16}}}} \Rightarrow {\mathtt{h}} = {\mathtt{11.313\: \!708\: \!498\: \!984\: \!760\: \!4}}$ cm

if the side of this isosceles triangle are 12cm and base is 8cm whats the height

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Best Answer

a = b = 12 cm ; c = 8 cm

Pythagoras: h² + (c/2)² = a²

h² = 144 - 16 => h = ${\sqrt{{\mathtt{144}}{\mathtt{\,-\,}}{\mathtt{16}}}}$

${\mathtt{h}} = {\sqrt{{\mathtt{144}}{\mathtt{\,-\,}}{\mathtt{16}}}} \Rightarrow {\mathtt{h}} = {\mathtt{11.313\: \!708\: \!498\: \!984\: \!760\: \!4}}$ cm

1⁺⁰ Answers

a = b = 12 cm ; c = 8 cm

Pythagoras: h² + (c/2)² = a²

h² = 144 - 16 => h = ${\sqrt{{\mathtt{144}}{\mathtt{\,-\,}}{\mathtt{16}}}}$

${\mathtt{h}} = {\sqrt{{\mathtt{144}}{\mathtt{\,-\,}}{\mathtt{16}}}} \Rightarrow {\mathtt{h}} = {\mathtt{11.313\: \!708\: \!498\: \!984\: \!760\: \!4}}$ cm

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if the side of this isosceles triangle are 12cm and base is 8cm whats the height

0 users composing answers..

Best Answer

a = b = 12 cm ; c = 8 cm

Pythagoras: h² + (c/2)² = a²

h² = 144 - 16 => h =√144−16{\sqrt{{\mathtt{144}}{\mathtt{\,-\,}}{\mathtt{16}}}}

h=√144−16⇒h=11.3137084989847604{\mathtt{h}} = {\sqrt{{\mathtt{144}}{\mathtt{\,-\,}}{\mathtt{16}}}} \Rightarrow {\mathtt{h}} = {\mathtt{11.313\: \!708\: \!498\: \!984\: \!760\: \!4}} cm

1+0 Answers

a = b = 12 cm ; c = 8 cm

Pythagoras: h² + (c/2)² = a²

h² = 144 - 16 => h =√144−16{\sqrt{{\mathtt{144}}{\mathtt{\,-\,}}{\mathtt{16}}}}

h=√144−16⇒h=11.3137084989847604{\mathtt{h}} = {\sqrt{{\mathtt{144}}{\mathtt{\,-\,}}{\mathtt{16}}}} \Rightarrow {\mathtt{h}} = {\mathtt{11.313\: \!708\: \!498\: \!984\: \!760\: \!4}} cm

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h² = 144 - 16 => h = ${\sqrt{{\mathtt{144}}{\mathtt{\,-\,}}{\mathtt{16}}}}$

${\mathtt{h}} = {\sqrt{{\mathtt{144}}{\mathtt{\,-\,}}{\mathtt{16}}}} \Rightarrow {\mathtt{h}} = {\mathtt{11.313\: \!708\: \!498\: \!984\: \!760\: \!4}}$ cm

1⁺⁰ Answers

h² = 144 - 16 => h = ${\sqrt{{\mathtt{144}}{\mathtt{\,-\,}}{\mathtt{16}}}}$

${\mathtt{h}} = {\sqrt{{\mathtt{144}}{\mathtt{\,-\,}}{\mathtt{16}}}} \Rightarrow {\mathtt{h}} = {\mathtt{11.313\: \!708\: \!498\: \!984\: \!760\: \!4}}$ cm