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If the sum of six consecutive EVEN integers is 282, then what is the largest of the integers? I saw a very similar question on here but using that formula gave me a decimal :(. help.

 Nov 21, 2019
 #1
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To simplify things........call the third integer 2N....so we have that

 

(2N-4) + (2N -2)) + (2N) + (2N + 2) + (2N + 4) + (2N + 6)   = 282

 

2N (6)  + 6  =  282      subtract 6 from both sides

 

12N  =  276   divide both side by 12

 

N =  23

 

So....the integers are

 

2(23) - 4  = 42   and then   44, 46, 48 , 50 , 52

 

 

cool cool cool

 Nov 21, 2019
 #2
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Thanks! I would give you credit but... I would be failed for cheating. But this helped a lot, thanks!

Guest Nov 21, 2019

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