If the sum of six consecutive EVEN integers is 282, then what is the largest of the integers? I saw a very similar question on here but using that formula gave me a decimal :(. help.

Guest Nov 21, 2019

#1**+1 **

To simplify things........call the third integer 2N....so we have that

(2N-4) + (2N -2)) + (2N) + (2N + 2) + (2N + 4) + (2N + 6) = 282

2N (6) + 6 = 282 subtract 6 from both sides

12N = 276 divide both side by 12

N = 23

So....the integers are

2(23) - 4 = 42 and then 44, 46, 48 , 50 , 52

CPhill Nov 21, 2019