If the system of equations\(\begin{align*}2x-y&=a,\\3y-6x &=b.\end{align*}\)has a solution, find a/b, assuming b is not 0.
2x - y = a ⇒ 6x - 3y = 3a (1)
3y - 6x = b (2)
Adding (1) and (2) we get that
0 = 3a + b
-3a = b
So
a / b =
a / (-3a ) =
- 1/ 3