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If the triangle below is dilated by a factor of 3/2 , what are the vertices of the transformed triangle?

https://s3.amazonaws.com/content.accelerate-ed.com/Secondary/docs/Geometry/images/LO4_6_Semester_Exam_Question1.png

 

 

(-3, 0), (6, 3), (6, -3)

(-2, 0) (4, 3), (6, -3)

(-3, 0), (6, 3), (9, -3)

(-3, -3), (4, 2), (9, -3)

Guest Jun 2, 2015

Best Answer 

 #2
avatar+92781 
+10

 

 

This is a dilation set about (0,0)

 

Melody  Jun 2, 2015
 #1
avatar+87301 
+10

(-3, 0), (6, 3), (9, -3)

 

Both coordinate values of every point are "expanded" by 3/2

 

So.......

 

(3/2) * (-2, 0)  = (-3, 0)

(3/2) * (4. 2)  =  (6, 3)

(3/2) * (6, -2) = (9, -3)

 

 

CPhill  Jun 2, 2015
 #2
avatar+92781 
+10
Best Answer

 

 

This is a dilation set about (0,0)

 

Melody  Jun 2, 2015
 #3
avatar+87301 
0

Nice pic, Melody......

 

 

CPhill  Jun 2, 2015
 #4
avatar+92781 
0

Thanks Chris :)

Melody  Jun 2, 2015

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