if (x -5) to the second power + (y + 2)to the second power = 64 what is the radius
+130511 if (x -5) to the second power + (y + 2)to the second power = 64 what is the radius
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So we have (x - 5)2 + (y + 2)2 = 64
The general equation of a circle is
(x - h)2 + (y - k)2 = r2 Where the center is (h,k) and r is the radius.
So, in our question, r2 = 64
Taking the (positive) square root of both sides, we have
r = 8
+130511 if (x -5) to the second power + (y + 2)to the second power = 64 what is the radius
---------------------------------------------------------------------------------------------------
So we have (x - 5)2 + (y + 2)2 = 64
The general equation of a circle is
(x - h)2 + (y - k)2 = r2 Where the center is (h,k) and r is the radius.
So, in our question, r2 = 64
Taking the (positive) square root of both sides, we have
r = 8
