if $${\frac{{\mathtt{x}}}{{\mathtt{2}}}}{\mathtt{\,-\,}}{\frac{{\mathtt{3}}}{{\mathtt{x}}}} = {\mathtt{5}}$$
what is $${\frac{{{\mathtt{x}}}^{{\mathtt{2}}}}{{\mathtt{4}}}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{9}}}{{{\mathtt{x}}}^{{\mathtt{2}}}}}$$ ?
+299 x/2-3/x=5
Multiply 2x to both sides
x^2-6=10x
Subtract 10x from both sides
x^2-10x-6=0
Add 6 to both sides
x^2-10x=6
→x(x-10)=6
x=$${\mathtt{5}}{\mathtt{\,\small\textbf+\,}}{\sqrt{{\mathtt{31}}}}$$ or $${\mathtt{5}}{\mathtt{\,-\,}}{\sqrt{{\mathtt{31}}}}$$
So, x^2/4+9/x^2=28
