You cannot calculate directly,
5x - 4y = 1x + 3y
5x - 1x = 3y + 4y
4x = 7y ...............(1)
suppose if we substitute the value of x as 5 in equation (1), we get,
20 = 7y
y = 20/7
OR we can substitute, y as 8 in equation (1), we get,
4x = 56
x = 56/4 = 14