If x= -sqrt(2) (-√2)

x^3-x^2-3x+1

[-sqrt(2)]^3 - [-sqrt(2)]^2 -3[-sqrt(2)] + 1 =

-2sqrt(2) - 2 + 3 sqrt(2) + 1  =

sqrt(2)  - 1

If x= -sqrt(2)  (-√2)

Then what is the value of the expression x^3-x^2-3x+1 (please show steps)? Thanks!

If x=-sqrt(2) (-sqrt(2)), Then x=2

When you ask "what is the value of the expression", do you actually want the "numerical value" of the your expression? If that is so, then we sustitute 2 for every x in the expression, and we get:

2^3 - 2^2 - 3 + 1=8 - 4 -3 + 1=-1 + 1=0. Good Luck.