if x + x + x = 30 ; x + 2y + 2y = 18 and 2y - 2z = 2 how much is y + x * z
X+X+X=30
3x=30
x=10
x+2y+2y=18
(10)+2y+2y=18
10+4y=18
4y=8
y=2
2y-2z=2
(2*2)-2z=2
4-2z=2
-2z=-2
z=1
y+x*z
2+10*1
2+10
12
+129839 if x + x + x = 30 ; x + 2y + 2y = 18 and 2y - 2z = 2 how much is y + x * z
So simplifying, we have
3x = 30 → x = 10
And
x + 4y = 18 → 10 + 4y = 18 → 4y = 8 → y = 2
And
2y - 2z = 2 → y - z = 1 → 2 - z = 1 → z = 2 - 1 = 1
So
y + x * z = 2 + 10 * 1 = 2 + 10 = 12
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if x + x + x = 30
~ 3x=30
---- x = 10
if x + 2y + 2y = 18
~ 10 + 2y + 2y=18
~ (2y + 2y) = 4y
~~ 10 + 4y = 18
~~ -10 -10
~~~ 4y = 8
~~~ divide both sides by 4
~~~~ y = 2
- check 10 + (2*2) + (2*2) = 18
-- 10 + 4 + 4 = 18
--- 18 = 18
---- y = 2
if 2y - 2z = 2
~ (2*2) - 2z = 2
~~ 4 - 2z = 2
~~ -4 -4
~~~ -2z = 2
~~~ divide both by 2
~~~~ -z = 1
~~~~ *-1 *-1
~~~~~ z = -1
---- z = -1
how much is ' y + x * z '
x = 10, y = 2, z = -1
~ 2 + 10 * -1
~ PEMDAS
~ 2 + (10*-1)
~~ 2 + (10 * -1)
~~~ 2 + ( -10 )
~~~~ ( -8 )
