if y=4x+41 and y=(x/3)-14, x=???
4x+41=(x/3)-14
multiply both sides by 3 to get rid of the fraction
3[4x+41]= 3 [(x/3)-14]
12x+123=x-42
subtract x from both sides
11x+123=-42
subtract 123 from both sides
11x=-42-123
11x=-165
divide both sides by 11
x=-165/11
x= - 15