+0  
 
0
57
1
avatar

\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}564\Pi 254\Leftrightarrow45\begin{pmatrix} 1\\ 2 \end{pmatrix}\begin{bmatrix} 1 && 2 \\ 3 && 4 \end{bmatrix}\)=

 Jan 28, 2020
edited by Guest  Jan 28, 2020
edited by Guest  Jan 28, 2020
 #1
avatar
0

 

  π r2 .... no, pie are round .... cornbread are square  

 Jan 29, 2020

55 Online Users

avatar
avatar
avatar