im not sure how to finish this problem

Albert's money:

1st line   Period is ONE month    total periods = 10 years x12 month/yr  = 120 periods

              Interst per period is .012/12 = .001

              Principle = 1000

              At the end of 10 years    value = 1000 (1.001)¹²⁰

2nd line   500 - 500(.02)

3rd line    Continuous compounding at .008     is  500 e^10(.008)  = $ 541.64

Add the red quantities to get Albert's final amount at the end of the ten years.....

thank you !