+128475 3^(2x - 1) = 36 * 2 (1 - 2x)
Note that we can write 2 ^(1-2x) = [ 2^(-1) ] ^(2x - 1) = 1 / [ 2^(2x - 1)]
So we have that
3^(2x - 1) = 36 / [ 2^(2x - 1)] multiply both sides by 2^(2x - 1)
3^(2x - 1) * 2^(2x - 1) = 36
3^(2x)/3 * 2^(2x) / 2 = 36
9^x * 4^x / 6 = 36 multiply both sides by 6
9^x * 4^x = 216
(9 * 4)^x = 216
36^x = 216
(6^2)^x = 6^3
6^(2x) = 6^3 equate exponents
2x = 3
x = 3/2
Can someone solve this please?
