What is the simplified numerical value of \(\frac{a+11b}{a-b}\) if \(\frac{4a+3b}{a-2b}=5\)?
If (4a + 3b) / (a - 2b) = 5
then 4a + 3b = 5(a - 2b)
4a + 3b = 5a - 10b
13b = a
Therefore, substituting 13b for a:
(a + 11b) / (a - b) = (13b + 11b) / (13b - b) = 24b / 12b = 2
Thank you!
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