+174 Determine the smallest non-negative integer that satisfies the congruences:
a≡2(mod3),a≡4(mod5),a≡6(mod7),a≡8(mod9).
Using Chinese Remainder Theorem with Modular Multiplicative Inverse which are incorporated into this short computer code, we get:
i=0;j=0;m=0;t=0;a=(3, 5,7, 9);r= (2, 4, 6, 8);c=lcm(a); d=c / a[i];n=d % a[i] ;loop1:m++; if(n*m % a[i] ==1, goto loop, goto loop1);loop:s=(c/a[i]*r[j]*m);i++;j++;t=t+s;m=0;if(i< count a, goto4,m=m);printc,"m + ",t % c;return
315 m + 314, where m =0, 1, 2, 3.......etc.
Then the smallest positive integer = 314
