+161 (a+bi)^2=2i
then you expand to \(\left(a^2-b^2\right)+2iab=2i\)
\(\left(a^2-b^2\right)+2iab=0+2i\)
then, let's write is as system of equations: (I assume you know what it is)
\(\begin{bmatrix}a^2-b^2=0\\ 2ab=2\end{bmatrix}\)
So, \(x=1+i,\:x=-1-i\)
Hope this made sense! :D
-tigernathan
