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Solve the following equation in full detail:

 

\(x^2 = 2i\)

 Aug 5, 2020
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(a+bi)^2=2i

then you expand to \(\left(a^2-b^2\right)+2iab=2i\)

\(\left(a^2-b^2\right)+2iab=0+2i\)

then, let's write is as system of equations: (I assume you know what it is)

\(\begin{bmatrix}a^2-b^2=0\\ 2ab=2\end{bmatrix}\)

So, \(x=1+i,\:x=-1-i\)

Hope this made sense! :D

 

-tigernathan

 Aug 5, 2020

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