+251 I have the function:
\(P(t)=\frac{10000}{1+9e^{-1.13t}}\)
I'm trying to solve for the time it takes to reach P = 10,000
that is,
\(\textrm{Solve for t}\\ 10000=\frac{10000}{1+9e^{-1.13t}}\)
after graphing I can see that the answer is t = 10, However I wish to solve this explicitly / analytically.
I get to the point of:
\(0 = e^{-1.13t}\)
and then I'm lost from there.
your help is greatly appreciated !
The only way you can get P(t) =10,000 is to have your denominator = 1 exactly!. Even if t =1,000,000
then you would have: e^(-1,130,000), which of course means: 1 / (e^1,130,000), which is very close to zero, but NOT exactly zero!. In fact e^(-1,130,000) =1.719686672 E-490,753.
