\(3x + xi − 2y = 12 − iy − i;\)
Please tell me how do i find x and y step by step
I know the method with the real part and the imaginary part but what should i do when the real part includes both x and y?
Thanks
Solve for x:
(3 + i) x - 2 y = (12 - i) + (0 - i) y
(3 + i) x - 2 y = (3 + 1 i) x - 2 y and (12 - i) + (0 - i) y = (0 - i) y + 12 - i:
(3 + 1 i) x - 2 y = (0 - i) y + 12 - i
Add 2 y to both sides:
(3 + i) x = (2 - i) y + 12 - i
Divide both sides by 3 + i:
Answer: |x = (1/2 - i/2) y + 7/2 - (3 i)/2
+37084 3x + xi - 2y = 12-iy-i add iy and i to both sides
3x + xi -2y +iy +i = 12 and 'reverse distributive property'
3x + i(x+y+1) -2y = 12 now you cannot do much more unless you have another equation relating x and y
to reach a discrete solution for x,y (though you can solve for x in terms of y or y in terms of x as guest 1 did above....but you cannot find an answer for x,y)
or you could say x(3+i) - y(2-i) + i = 12
