what is the answer to 1+i divided by 1-2i
\(\frac{1+i }{1-2i}\\ =\frac{1+i }{1-2i}\times\frac{1+2i}{1+2i}\\ =\frac{(1+i)(1+2i) }{(1-2i)(1+2i)}\\ =\frac{1(1+2i) +i(1+2i)}{1-4(i^2)}\\ =\frac{1+2i +i-2}{1+4}\\ =\frac{-1+3i }{5}\\ =\frac{-1 }{5}+\frac{3 }{5}i \)
