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Can you solve this smultaneous linear equation by using the elimination, please?

 

Thanks!

 

y + z + w = 6

z +2w + x = 8

3w + x + y =10

x + y + z = 9

 

 

I found this very hard!

 Jun 3, 2016
 #1
avatar+33661 
+5

1).       w + y + z  = 6   

2).       2w + x + z = 8

3).      3w + x + y =10

4).       x + y + z = 9

 

5).          3). - 4).     3w - z = 1     

6).          1) + 2).     3w + x+ y + 2z = 14   

 

From 4) we have x+ y = 9 - z  so, using this in 6). we have:    3w + 9 - z + 2z = 14  or:

7)         3w + z = 5

 

8).         7). - 6).        2z = 4    hence  z = 2

 

Put this into 7) to get  3w + 2 = 5  or  3w = 3   or w = 1

 

Put these back into 1) to get  1 + y + 2 = 6   so  y = 3

 

and into 2) to get  2 + x + 2 = 8  or  x = 4

.

 Jun 3, 2016
 #2
avatar+33661 
0

I've just noticed this question has been asked and answered earlier.

 

Please don't post the same question twice!!

Alan  Jun 3, 2016

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