+204 Can you solve this smultaneous linear equation by using the elimination, please?
Thanks!
y + z + w = 6
z +2w + x = 8
3w + x + y =10
x + y + z = 9
I found this very hard!
+33616 1). w + y + z = 6
2). 2w + x + z = 8
3). 3w + x + y =10
4). x + y + z = 9
5). 3). - 4). 3w - z = 1
6). 1) + 2). 3w + x+ y + 2z = 14
From 4) we have x+ y = 9 - z so, using this in 6). we have: 3w + 9 - z + 2z = 14 or:
7) 3w + z = 5
8). 7). - 6). 2z = 4 hence z = 2
Put this into 7) to get 3w + 2 = 5 or 3w = 3 or w = 1
Put these back into 1) to get 1 + y + 2 = 6 so y = 3
and into 2) to get 2 + x + 2 = 8 or x = 4
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