\(sin(xy)=x+y\)
I'm having loads of trouble figuring out implicit derivatives.
Could someone please work out this problem in great detail? I'm a slow learner on hard stuff
Thanks so much
sin (xy) = x + y
Use the Chain Rule on the left
cos(xy) *[ xy' + y ] = 1 + y'
cos(xy) * xy' + cos(xy)*y = 1 + y' ....collect the y' terms on the left.....
xy' cos(xy) - y' = 1 - y* cos(xy)
y ' [ x*cos (xy) - 1 ] = 1 - y* cos(xy)
y ' = [ 1 - y* cos(xy) ]
_____________
x* cos(xy) - 1