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i got the first part but need help on the second part of the question :(

 

 
 Oct 14, 2021
 #1
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+1

The algebra was vile and I likely made a careless error but I got

 

\(\displaystyle \frac{d^2y}{dx^2}=\frac{0.5-6y^{0.5}+24y-32y^{1.5}}{(1-16y)^3}\)

 

 

You don't need y' in your answer because you already know its value from the first part of the question.

 
 Oct 14, 2021
edited by Melody  Oct 14, 2021

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