In a sale, a shopkeeper reduced the marked price of his goods by 20%. The price of a camera in the sale was $60. calculate its marked price?
+354 If a camera was reduced by 20%, then the equation would be:
$${\mathtt{X}}{\mathtt{\,\times\,}}\left({\mathtt{1}}{\mathtt{\,-\,}}{\mathtt{0.2}}\right) = {\mathtt{60}}$$
We simply rearrange to find X.
$${\mathtt{x}} = {\frac{{\mathtt{60}}}{{\mathtt{0.8}}}} \Rightarrow {\mathtt{x}} = {\mathtt{75}}$$
So the original price was £75
+354 If a camera was reduced by 20%, then the equation would be:
$${\mathtt{X}}{\mathtt{\,\times\,}}\left({\mathtt{1}}{\mathtt{\,-\,}}{\mathtt{0.2}}\right) = {\mathtt{60}}$$
We simply rearrange to find X.
$${\mathtt{x}} = {\frac{{\mathtt{60}}}{{\mathtt{0.8}}}} \Rightarrow {\mathtt{x}} = {\mathtt{75}}$$
So the original price was £75
