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In a triangle ABC is

 

a) Determine the angles when cos A = 3 sin A

 

b) Determine the angles when their A = 3 cos A

 Feb 7, 2019
edited by Guest  Feb 7, 2019

Best Answer 

 #1
avatar+18965 
+1

Assuming we are working with a RIGHT triangle:

 

cos a = 3 sin a

1/3 = tan a = sin /cos

 

arctan(1/3) = 18.43 degrees    

     18.43   + 90 + x = 180      x = 71.57 degrees       and the 90 degree angle

 

 

sin a = 3 cos a

 

sin/cos = 3

arctan(3) =  71.57 degrees     and 18.43 degrees and 90 degrees    (as before)  

 Feb 7, 2019
edited by ElectricPavlov  Feb 7, 2019
edited by ElectricPavlov  Feb 7, 2019
 #1
avatar+18965 
+1
Best Answer

Assuming we are working with a RIGHT triangle:

 

cos a = 3 sin a

1/3 = tan a = sin /cos

 

arctan(1/3) = 18.43 degrees    

     18.43   + 90 + x = 180      x = 71.57 degrees       and the 90 degree angle

 

 

sin a = 3 cos a

 

sin/cos = 3

arctan(3) =  71.57 degrees     and 18.43 degrees and 90 degrees    (as before)  

ElectricPavlov Feb 7, 2019
edited by ElectricPavlov  Feb 7, 2019
edited by ElectricPavlov  Feb 7, 2019
 #2
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thank you again!!

 Feb 7, 2019

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