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# In a triangle ABC is

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In a triangle ABC is

a) Determine the angles when cos A = 3 sin A

b) Determine the angles when their A = 3 cos A

Feb 7, 2019
edited by Guest  Feb 7, 2019

#1
+25992
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Assuming we are working with a RIGHT triangle:

cos a = 3 sin a

1/3 = tan a = sin /cos

arctan(1/3) = 18.43 degrees

18.43   + 90 + x = 180      x = 71.57 degrees       and the 90 degree angle

sin a = 3 cos a

sin/cos = 3

arctan(3) =  71.57 degrees     and 18.43 degrees and 90 degrees    (as before)

Feb 7, 2019
edited by ElectricPavlov  Feb 7, 2019
edited by ElectricPavlov  Feb 7, 2019

#1
+25992
0

Assuming we are working with a RIGHT triangle:

cos a = 3 sin a

1/3 = tan a = sin /cos

arctan(1/3) = 18.43 degrees

18.43   + 90 + x = 180      x = 71.57 degrees       and the 90 degree angle

sin a = 3 cos a

sin/cos = 3

arctan(3) =  71.57 degrees     and 18.43 degrees and 90 degrees    (as before)

ElectricPavlov Feb 7, 2019
edited by ElectricPavlov  Feb 7, 2019
edited by ElectricPavlov  Feb 7, 2019
#2
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thank you again!!

Feb 7, 2019