In a triangle ABC is

a) Determine the angles when cos A = 3 sin A

b) Determine the angles when their A = 3 cos A

Guest Feb 7, 2019

edited by
Guest
Feb 7, 2019

#1**+1 **

Assuming we are working with a RIGHT triangle:

cos a = 3 sin a

1/3 = tan a = sin /cos

arctan(1/3) = 18.43 degrees

18.43 + 90 + x = 180 x = 71.57 degrees and the 90 degree angle

sin a = 3 cos a

sin/cos = 3

arctan(3) = 71.57 degrees and 18.43 degrees and 90 degrees (as before)

ElectricPavlov Feb 7, 2019

#1**+1 **

Best Answer

Assuming we are working with a RIGHT triangle:

cos a = 3 sin a

1/3 = tan a = sin /cos

arctan(1/3) = 18.43 degrees

18.43 + 90 + x = 180 x = 71.57 degrees and the 90 degree angle

sin a = 3 cos a

sin/cos = 3

arctan(3) = 71.57 degrees and 18.43 degrees and 90 degrees (as before)

ElectricPavlov Feb 7, 2019