In △ABC, AB=6 cm, AC=15 cm, and m∠A=48°. What is the area of △ABC?
Round only your final answer to the nearest hundredth.
Let's let the base of this triangle be 15 cm, and the height be the skinny purple line.
sin θ = opposite / hypotenuse
sin 48º = height / 6
6 sin 48º = height
area = (1/2)(base)(height)
area = (1/2)(15)(6 sin 48º)
area ≈ 33.44 cm2
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