+0  
 
0
767
5
avatar+149 

In △ABC, AB=6 cm, AC=15 cm, and m∠A=48°. What is the area of △ABC?

Round only your final answer to the nearest hundredth.

Kakarot_15  May 28, 2017
 #1
avatar+7324 
+2

 

Let's let the base of this triangle be 15 cm, and the height be the skinny purple line.

 

sin θ = opposite / hypotenuse

sin 48º    = height / 6

6 sin 48º = height

 

area = (1/2)(base)(height)

area = (1/2)(15)(6 sin 48º)

 

area ≈ 33.44 cm2

hectictar  May 28, 2017
 #2
avatar
+1

hectictar: You are one brilliant young lady and will amount to something great someday! I congratulate you.

Guest May 28, 2017
 #3
avatar+7324 
+2

Wow! Thank you Guest, I sure do appreciate that! smiley

hectictar  May 28, 2017
 #4
avatar
+1

Yes, she will. However, H. is already something great – This is visible in the present. Her future holds boundless wonders.

Guest May 28, 2017
 #5
avatar+7324 
+1

Haha! I do my fair share of dumb things too! But thanks smiley

hectictar  May 28, 2017

24 Online Users

avatar
avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.