In ABC, we have AB=16, BC=14, and Angle A=60. Find the sum of all possible values of AC.
Let the line segment CD be perpendicular to AB.
AD = x
x√3 = sqrt[142 - (16 - x)2]
x = 3, x = 5
AC = 3/cos(60º) = 6
AC = 5/cos(60º) = 10
The sum of all possible values of AC = 16
