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avatar+143 
In an engineering test, a rocket sled is propelled into a target.  The sled’s distance  d in meters from the target is given by the formula  d = -1.5 t 2 + 120, where  is the number of seconds after rocket ignition.  How many seconds have passed since rocket ignition when the sled is 10 meters from the target?

 

















a.


about 6.74 seconds


c.


about 4.82 seconds


b.


about 8.56 seconds


d.


about 1.39 seconds

 Dec 15, 2014

Best Answer 

 #1
avatar+128597 
+5

We have

  d = -1.5 t 2 + 120    and when d = 10, we have

10 = -1.5t^2 + 120   rearrange

1.5t^2 -110  = 0

Add 110  to both sides

1.5t^2 = 110     divide both sides by 1.5

t^2  = 110/1.5      take the positive root of both sides

t = √(110/1.5)  =  about 8.56 seconds

 

 Dec 15, 2014
 #1
avatar+128597 
+5
Best Answer

We have

  d = -1.5 t 2 + 120    and when d = 10, we have

10 = -1.5t^2 + 120   rearrange

1.5t^2 -110  = 0

Add 110  to both sides

1.5t^2 = 110     divide both sides by 1.5

t^2  = 110/1.5      take the positive root of both sides

t = √(110/1.5)  =  about 8.56 seconds

 

CPhill Dec 15, 2014

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