In isosceles right triangle ABC, point D is on hypotenuse line BC such that line AD is an altitude of triangle ABC and DC = 5. What is the area of triangle ABC?
I've been working on this one for a while. Any help is appeciated!
Since it is an isoc right triangle the two legs are the same length (and the angles of the triangle are 90 45 45) Line DC = 5 Line BD = 5 AND Line AD will equal 5
Area of smaller triangle = 1/2 (5)(5) Total area will be the sum of the two small triangles (which are identical) 2 x 1/2 5 x 5 = 25 units^2