In pentagon MATHS, angle M = angle T = angle H and angle A + angle S = 58 degrees. How many degrees are in the measure of angle H?
The interior angles of a pentagon sum to 540°
So.....let X be the measure of angle M , angle T and angle H......and we have that
X + X + X + 58 = 540
3X + 58 = 540 subtract 58 from both sides
3X = 482 divide both sides by 3
X = 482/3 = ( 160 + 2/3 )° = measure of angle H