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In right △ABC, the right angle is at C, m∠A=30∘, and AC=7√2 units.

What is the perimeter of △ABC?

 Feb 14, 2021
 #1
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Not sure if you've heard of 30 60 90 triangles, so if you haven't, you can look it up :)

Since we know it's a right triangle, and one of the angles is 30, this triangle is a 30 60 90 triangle. 

If AC = 7√2, BC = (7√2) / √3, and BA = 2(BC)

BC = (7√2) / √3 
      = (7√6) / 3

BA = 2 * ((7√6) / 3)
      = (14√6) / 3

 

This means the perimeter of the triangle = 7√2 + (7√6) / 3 + (14√6) / 3
                                                                 = 7(√6 + √2) units

Hope this helps :)

P.S. I still haven't found out how to type fractions neatly, so I'm sorry if it's a bit hard to follow :(

 Feb 14, 2021

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