In right triangle PQR, we have angle Q = angle R and PR = 6sqrt(2). What is the area of triangle PQR?

The area of triangle PQR is 1/2*6^2 = 18.

QR/2 = cos(45°) * 6sqrt(2) = 6

Height of triangle h = sin(45°) * 6sqrt(2) = 6

The area of triangle PQR = 6² = 36 u² _{}