+0  
 
+1
24
2
avatar+115 

In right triangle PQR, we have angle Q = angle R and PR = 6sqrt(2). What is the area of triangle PQR?

 Feb 15, 2020
 #1
avatar
0

The area of triangle PQR is 1/2*6^2 = 18.

 
 Feb 15, 2020
 #2
avatar+319 
+1

QR/2 = cos(45°) * 6sqrt(2) = 6

Height of triangle  h = sin(45°) * 6sqrt(2) = 6

The area of triangle PQR = 6² = 36 u²   indecision

 
Dragan  Feb 15, 2020
edited by Guest  Feb 15, 2020

26 Online Users

avatar