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In right triangle PQR, we have angle Q = angle R and PR = 6sqrt(2). What is the area of triangle PQR?

 Feb 15, 2020
 #1
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The area of triangle PQR is 1/2*6^2 = 18.

 Feb 15, 2020
 #2
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QR/2 = cos(45°) * 6sqrt(2) = 6

Height of triangle  h = sin(45°) * 6sqrt(2) = 6

The area of triangle PQR = 6² = 36 u²   indecision

Dragan  Feb 15, 2020
edited by Guest  Feb 15, 2020

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