In terms of \(\pi\), what is the area of the circle defined by the equation \(2x^2+2y^2+10x-6y-18=0\)?
+36916 2x^2 + 10x + 2y^2-6y = 18 divide by 2
x^2 + 5x + y^2 -3y = 9 complete the squares
(x+2.5)^2 + (y-1.5)^2 = 9 + 6.25 + 2.25
= 17.5 = r^2 area = pi r^2 = 17.5 pi
