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In the expansion of (x+1)^42 what is the coefficient of the x^2  term?

 Sep 18, 2016
 #1
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In the expansion of (x+1)^42 what is the coefficient of the x^2  term?

 

=861x^2

 Sep 18, 2016
 #2
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In (x+1)^42, 42^2 multiplications take place.

 

The relevant multiplications in this case are those that are x * x * 1^40 (= x * x * 1 = x^2)

 

So in each of the relevant multiplication, 2 x terms are multiplied and 40 "1" terms are multiplied.

 

This can be modeled onto a combinations problem of how many different ways there are to take 2 objects (x terms) from a group of 42 unqiue objects.

 

I don't know how to solve this, but I do know how to model it, so hopefully someone can take over from here.

 Sep 18, 2016
 #3
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The coefficients are simply the binomial coefficients of: 42C1, 42C2, 42C3...........42C42.

 Sep 18, 2016
 #4
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In the expansion of (x+1)^42 what is the coefficient of the x^2 term?

 

x² * c = (x + 1)42 

 

\(c=\frac{\left(x+1\right) ^{42} }{x^{2} } \)

    

Unfortunately I do not see Walkthrough.

asinus laugh !

 Sep 18, 2016

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