In trapezoid ABCD, sides AB and CD are parallel, \(\angle{A}\) = \(2\angle{D}\), and \(\angle{C}\) = \(3\angle{B}\). Find \(\angle{A}\).
Since AB and CD are parallel
Then angles A and D are supplemental ....so
A + D = 180
2D + D = 180
3D = 180
D = 60
And A = 2D = 2(60) = 120°
+239 
