In trapezoid ABCD , sides \(\overline{AB}\) and \(\overline{CD}\) are parallel, \(\angle A = 2\angle D\) , and \(\angle C = 3\angle B\) . Find \(\angle B\).
In trapezoid ABCD , sides AB and CD are parallel, Find \(\delta \)
Since AB is parallel to CD, then
A + D = 180 and
B + C = 180
Then
2D + D = 180
3D = 180
D = 60°
And
B + 3B = 180
4B = 180
B = 45°