In triangle A B C , A B = 6 and B C = 8. Find A C if angle B is 30 degrees.

Find AC:

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The solution is the law of cosines.

\(b^2=a^2+c^2-2ac\ cos\ \beta\\ b=\sqrt{8^2+6^2-2\cdot 8\cdot 6\cdot cos\ 30^{\circ}}\\ \color{blue}\overline{AC}=b=4.106\)

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