In triangle ABC, sin A= 12/13. What is cos B?

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Guest Apr 20, 2015

+23247

+5

Best Answer

If sin(A) = 12/13, then the value of the side opposite angle A is 12 and the value of the hypotenuse is 13.

To find the third side (the side adjacent to angle A) can be found by using the Pythagorean Theorem:

c² = a² + b² ---> 13² = 12² + b² ---> 169 = 144 + b² ---> b² = 25 ---> b = 5

Since the adjacent side has a value of 5 and the hypotenuse has a value of 13,

cos(A) = adj/hyp = 5/13.

geno3141 Apr 20, 2015

geno3141 · Answer 1 · 2015-04-20T07:48:48

If sin(A) = 12/13, then the value of the side opposite angle A is 12 and the value of the hypotenuse is 13.

To find the third side (the side adjacent to angle A) can be found by using the Pythagorean Theorem:

c² = a² + b² ---> 13² = 12² + b² ---> 169 = 144 + b² ---> b² = 25 ---> b = 5

Since the adjacent side has a value of 5 and the hypotenuse has a value of 13,

cos(A) = adj/hyp = 5/13.

Guest · Answer 2 · 2015-04-20T06:51:10

???????? IDK Ask someone who is smart.